0=36+24x+(10x^2)/2

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Solution for 0=36+24x+(10x^2)/2 equation: 


x in (-oo:+oo)

0 = (10*x^2)/2+24*x+36 // - (10*x^2)/2+24*x+36

0-((10*x^2)/2)-(24*x)-36 = 0

-5*x^2-24*x-36 = 0

-5*x^2-24*x-36 = 0

DELTA = (-24)^2-(-36*(-5)*4)

DELTA = -144

DELTA < 0

x belongs to the empty set

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